0.3 liters of kerosene burns in a kerosene stove per hour. What is the total power of the primus

0.3 liters of kerosene burns in a kerosene stove per hour. What is the total power of the primus if q (kerosene) = 4.6 × 10 ^ 7 J / kg?

We will work with this formula: A = Q = P * t

Let’s translate some data into SI and write additional ones:

t = 1 h = 3600 s

V = 0.3 L = 0.0003 m ^ 3

p = 800 kg / m ^ 3

m = p * V

We express the power P through the above formula: P = Q / t

Q = q * m = q * V * p. We get: P = q * V * p / t = 4.6 * 10 ^ 7 * 800 * 0.0003 / 3600 = ~ 3066 W.