0.3 liters of kerosene burns in a kerosene stove per hour. What is the total power of the primus if q (kerosene) = 4.6 × 10 ^ 7 J / kg?
We will work with this formula: A = Q = P * t
Let’s translate some data into SI and write additional ones:
t = 1 h = 3600 s
V = 0.3 L = 0.0003 m ^ 3
p = 800 kg / m ^ 3
m = p * V
We express the power P through the above formula: P = Q / t
Q = q * m = q * V * p. We get: P = q * V * p / t = 4.6 * 10 ^ 7 * 800 * 0.0003 / 3600 = ~ 3066 W.
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