10 lamps with a resistance of 100 Ohm each are connected in series to a network with a voltage of 220 V. Determine the equivalent circuit resistance, the amperage in each lamp and the total amperage consumed by all lamps.
U = 220 V.
n = 100.
R1 = 100 ohms.
With a series connection of conductors, the total resistance of the circuit R is the sum of the resistances of all series-connected conductors: R = R1 + R2 + … + Rn.
Since all connected resistances are the same, then R = n * R1, where n is the number of connected resistors.
R = 100 * 100 Ohm = 10000 Ohm.
We find the current strength I according to Ohm’s law: I = U / R = U / n * R1.
I = 220 V / 100 * 100 Ohm = 0.022 A.
With a series connection, the current I on all conductors is the same: I = I1 = I2 = … = In.
I = I1 = I2 = … = In = 0.022 A.
Answer: R = 10000 Ohm, I = I1 = I2 = … = In = 0.022 A.
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