10 mol of ideal monatomic gas was first cooled and then heated to an initial temperature of 300K

10 mol of ideal monatomic gas was first cooled and then heated to an initial temperature of 300K, increasing the gas volume by 3 times. Calculate the amount of heat in the process 1-3

To solve this task, we need to perform the following actions:
According to the first law of thermodynamics and the condition that the gas is ideal and monatomic, we have: Q23 = tr. U23 + A23, tr. U23 = 3/2 * vR * pipe T23,
A23 = P2 tr. V23 = vR * tr. T23, with tr. T23 = tr. T21.
Therefore Q23 = 5/2 * vR * tr. T21.
According to Charles’s law, P1 / T1 = P2 / T2, or T2 / T1 = P2 / P1 = 1/3;
T2 = T1 / 3, tr. T21 = 2/3 * T1 and Q23 = 5/3 * vRT1 = 5/3 * 10 * 8.31 * 300 = 41,550 J;
This is the final answer to the task given to us.