10 mol of ideal monatomic gas was first cooled and then heated to an initial temperature of 300K, increasing the gas volume by 3 times. Calculate the amount of heat in the process 1-3
To solve this task, we need to perform the following actions:
According to the first law of thermodynamics and the condition that the gas is ideal and monatomic, we have: Q23 = tr. U23 + A23, tr. U23 = 3/2 * vR * pipe T23,
A23 = P2 tr. V23 = vR * tr. T23, with tr. T23 = tr. T21.
Therefore Q23 = 5/2 * vR * tr. T21.
According to Charles’s law, P1 / T1 = P2 / T2, or T2 / T1 = P2 / P1 = 1/3;
T2 = T1 / 3, tr. T21 = 2/3 * T1 and Q23 = 5/3 * vRT1 = 5/3 * 10 * 8.31 * 300 = 41,550 J;
This is the final answer to the task given to us.
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