# 108 (kg) of calcium carbonate was calcined with silicon oxide (IV). Determine the amount

108 (kg) of calcium carbonate was calcined with silicon oxide (IV). Determine the amount of substance and the mass of the formed calcium silicate.

The reaction of obtaining calcium silicate by fusing soda with sand is described by the following equation:

CaCO3 + SiO2 = CaSiO3 + CO2;

Let’s calculate the chemical amount of calcium carbonate:

For this purpose, we divide its weight by the mass of 1 mole of the substance.

М СaСO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

n СaСO3 = 108,000 / 100 = 108 mol;

From this amount of calcium carbonate, the same amount of calcium silicate, equal to 108 mol, can be obtained.

Let’s determine its weight.

М СaSiO3 = 40 + 28 + 16 x 3 = 116 grams / mol;

m СaSiO3 = 108 х 116 = 12 528 grams = 12.528 kg;

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