1800 g of silicon oxide (IV) was fused with an excess of potassium hydroxide, resulting in the reaction of potassium silicate weighing 3.82 kg. Determine the yield of the reaction product.
When silicon dioxide and potassium hydroxide react, we get potassium silicate and water.
Let’s compose the reaction equation for calculating the theoretically possible mass of potassium silicate based on the reacting substances:
SiO2 + 2KOH = K2SiO3 + H2O. Find the mass of potassium silicate by the reaction equation.
K2SiO3 mass = 1800 * 154/60 = 4620 grams.
We divide the practically obtained mass of the product by the theoretically possible mass to find the yield of the product by the reaction: n = (3820 grams / 4620 grams) * 100% = 82.7%.
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