2 liters of a solution with a density of 1.11 g / cm3 contains 150 g of a soluble substance

2 liters of a solution with a density of 1.11 g / cm3 contains 150 g of a soluble substance. Find the mass fraction of the substance in the solution.

1. Knowing the volume and density, you can find the mass. using the formula:

m (solution) = V * ρ;

2.Let us convert the units of measurement to one type:

1 l = 1 dm3 = 1000 cm3;

V = 2000 cm3;

3.Calculate the mass of the solution:

m (solution) = 2000 * 1.11 = 2220 g;

4.The mass fraction of the solute is calculated by the formula:

w (substances) = m (substances): m (solution);

w (substances) = 150: 2220 = 0.0676 or 6.76%.

Answer: 6.76%.