28.2 g of monovalent metal oxide reacted with 0.3 mol of acid, naya metal

Let’s assume that this acid was hydrochloric acid. We write down the reaction equation.

Me2O + 2HCl = 2MeCl + H2O.

Determine the mass of the acid. To do this, use the following formula.

n = m / M.

m = n * M.

M (HCl) = 36.5 g / mol.

n = 0.3 * 36.5 = 10.95 g.

Next, we determine the molar mass of the metal. We make up the proportion.

28.2 g of metal oxide 10.95 g of acid.

2x + 16 g / mol of metal oxide – 2 * 36.5 g / mol.

(2x + 16) * 10.95 = 28.2 * 2 * 36.5.

(2x + 16) * 10.95 = 2058.6.

2x + 16 = 2058.6 / 10.95.

2x + 16 = 188.

2x = 172.

X = 86.

Answer: Rb rubidium.



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