1. The interaction of calcium oxide with water proceeds according to the equation:
CaO + H2O = Ca (OH) 2;
2.find the chemical amount of calcium oxide:
n (CaO) = m (CaO): M (CaO);
M (CaO) = 40 + 16 = 56 g / mol;
n (CaO) = 28: 56 = 0.5 mol;
3.determine the amount of calcium hydroxide obtained:
n (Ca (OH) 2) = n (CaO) = 0.5 mol;
4.Calculate the mass of calcium hydroxide:
m (Ca (OH) 2) = n (Ca (OH) 2) * M (Ca (OH) 2);
M (Ca (OH) 2) = 40 + 2 * 17 = 74 g / mol;
m (Ca (OH) 2) = 0.5 * 74 = 37 g.
Answer: 37 g.
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