40 g of 10% sulfuric acid solution reacts with barium chloride. determine the mass of the sediment formed.
July 28, 2021 | education
| H2SO4 + BaCl2 → BaSO4 ↓ + 2HCl
Let’s calculate the mass of sulfuric acid in solution:
m (H2SO4) = (40 g × 10%): 100% = 4 g.
Find the molar mass of sulfuric acid:
M (H2SO4) = 1 × 2 + 32 × 1 + 16 × 4 = 98 g / mol.
Let’s calculate the amount of sulfuric acid:
n (H2SO4) = m (H2SO4): M (H2SO4) = 4: 98 = 0.041 mol.
According to the reaction equation, the amount of sulfuric acid and the amount of precipitate (BaSO4) relate to each other as 1: 1. This means that 0.041 mol of sulfuric acid will yield 0.041 mol of precipitate.
Find the molar mass of barium sulfate:
M (BaSO4) = 137 × 1 + 32 × 1 + 16 × 4 = 233 g / mol.
Let’s calculate the mass of the sediment:
m (BaSO4) = n (BaSO4) × M (BaSO4) = 0.041 × 233 = 9.55 g.
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