40 g of 10% sulfuric acid solution reacts with barium chloride. determine the mass of the sediment formed.

H2SO4 + BaCl2 → BaSO4 ↓ + 2HCl

Let’s calculate the mass of sulfuric acid in solution:

m (H2SO4) = (40 g × 10%): 100% = 4 g.

Find the molar mass of sulfuric acid:

M (H2SO4) = 1 × 2 + 32 × 1 + 16 × 4 = 98 g / mol.

Let’s calculate the amount of sulfuric acid:

n (H2SO4) = m (H2SO4): M (H2SO4) = 4: 98 = 0.041 mol.

According to the reaction equation, the amount of sulfuric acid and the amount of precipitate (BaSO4) relate to each other as 1: 1. This means that 0.041 mol of sulfuric acid will yield 0.041 mol of precipitate.

Find the molar mass of barium sulfate:

M (BaSO4) = 137 × 1 + 32 × 1 + 16 × 4 = 233 g / mol.

Let’s calculate the mass of the sediment:

m (BaSO4) = n (BaSO4) × M (BaSO4) = 0.041 × 233 = 9.55 g.