43.4 g of mercury oxide (||) was decomposed. Calculate the number of moles of oxygen formed by the reaction

The decomposition equation for mercury oxide: 2HgO = 2Hg + O2.
1) The molecular weight of mercury is: 200.6.
2) Molecular weight of oxygen: 16.
3) Molecular weight of mercury oxide: 200.6 + 16 = 216.6.
4) The amount of mercury oxide substance: 43.4 / 216.6 = 0.2 mol.
5) The amount of oxygen is equal to: 0.2 / 2 = 0.1 mol – the answer.




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