46 g of sodium entered the reaction, calculate how much sulfur is required. Reaction equation: 2Mg + O2 – 2MgO

2Mg + O2 = 2MgO
V (amount of substance) Mg = m / M = 12/24 = 0.5 mol
M (Mg) = 24 g / mol
V (MgO) = 2 * 0.5 = 1 mol
m (MgO) = M * V = 40 * 0.5 = 20 grams
Answer: m (MgO) = 20 grams



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