1. Let’s compose the reaction equation:
2NaCl + H2SO4 = Na2SO4 + 2HCl ↑;
2.Calculate the chemical amount of sodium chloride:
n (NaCl) = m (NaCl): M (NaCl);
M (NaCl) = 23 + 35.5 = 58.5 g / mol;
n (NaCl) = 5.85: 58.5 = 0.1 mol;
3.Set the chemical amount of hydrogen chloride released:
n (HCl) = n (NaCl) = 0.1 mol;
4.determine the volume of hydrogen chloride:
V (HCl) = n (HCl) * Vm = 0.1 * 22.4 = 2.24 liters.
Answer: 2.24 liters.
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