Sodium is an active alkali metal. Reacts violently with water to form sodium hydroxide and hydrogen gas. The equation for this reaction is as follows:
2 Na + 2 H2O = 2 NaOH + H2
The molar masses of the substances are as follows ?:
Sodium = 23 g / mol;
sodium hydroxide = 40 g / mol;
hydrogen = 2 g / mol.
According to the reaction equation, we will compose the proportion to find the mass of alkali.
5 g of sodium corresponds to X g of sodium hydroxide as
2 * 23 g / mol sodium corresponds to 2 * 40 g / mol sodium hydroxide
X = (5 * 2 * 40) / (2 * 23) = 8.7 g of sodium hydroxide
Now we will find the volume of the evolved hydrogen gas. Molar volume of gas = 22.4 L / mol
5 g of sodium corresponds to Y l. hydrogen like
2 * 23 g / mol sodium corresponds to 22.4 l / mol hydrogen
Y = 5 * 22.4 / (2 * 23) = 2.4 liters. hydrogen.
Answer: 8.7 g of sodium hydroxide and 2.4 liters. hydrogen.
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