60 g of magnesium and 60 l of nitrogen reacted. Calculate the mass of the obtained magnesium nitride.

1. Let’s write the equation of the reaction of magnesium with nitrogen:

3Mg + N2 = Mg3N2;

2. calculate the chemical quantities:

n (Mg) = m (Mg): M (Mg) = 60: 24 = 2.5 mol;

n (N2) = V (N2): Vm = 60: 22.4 = 2.6786 mol;

3.According to the reaction equation and the found amounts of substances, magnesium is deficient, we determine the amount of magnesium nitride obtained:

n (Mg3N2) = n (Mg): 3 = 2.6786: 3 = 0.8629 mol;

4.calculate the mass of magnesium nitride:

m (Mg3N2) = n (Mg3N2) * M (Mg3N2);

M (Mg3N2) = 24 * 3 + 2 * 14 = 100 g / mol;

m (Mg3N2) = 0.8629 * 100 = 86.29 g.

Answer: 86.29 g.