# 7.2 g of Zn was added to a solution containing 9.8 g of H2SO4. What thing and how much

September 15, 2021 | education

| **7.2 g of Zn was added to a solution containing 9.8 g of H2SO4. What thing and how much will remain in excess? how much ZnSO4 is formed?**

Let’s implement the solution:

1. We write down the equation:

H2SO4 + Zn = ZnSO4 + H2 – substitution, hydrogen, zinc sulfate is formed;

2. Calculations:

M (H2SO4) = 98 g / mol.

M (Zn) = 65.3 g / mol.

M (ZnSO4) = 161.3 g / mol.

3. Determine Y (mol) of the starting materials, if the mass is known:

Y (H2SO4) = m / M = 9.8 / 98 = 0.1 mol.

Y (ZnSO4) = 0.1 mol since the amount of substances according to the equation is 1 mol.

Y (Zn) = m / M = 7.2 / 65.3 = 0.1 mol.

4. Find the mass of salt:

m (ZnSO4) = Y * M = 0.1 * 161.3 = 16.13 g.

Answer: zinc sulfate with a mass of 16.13 g was obtained.

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