7.2 g of Zn was added to a solution containing 9.8 g of H2SO4. What thing and how much will remain in excess? how much ZnSO4 is formed?
Let’s implement the solution:
1. We write down the equation:
H2SO4 + Zn = ZnSO4 + H2 – substitution, hydrogen, zinc sulfate is formed;
M (H2SO4) = 98 g / mol.
M (Zn) = 65.3 g / mol.
M (ZnSO4) = 161.3 g / mol.
3. Determine Y (mol) of the starting materials, if the mass is known:
Y (H2SO4) = m / M = 9.8 / 98 = 0.1 mol.
Y (ZnSO4) = 0.1 mol since the amount of substances according to the equation is 1 mol.
Y (Zn) = m / M = 7.2 / 65.3 = 0.1 mol.
4. Find the mass of salt:
m (ZnSO4) = Y * M = 0.1 * 161.3 = 16.13 g.
Answer: zinc sulfate with a mass of 16.13 g was obtained.
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