# A bar measuring 0.5 * 0.4 * 0.1 m is in a jar of water at a depth of 0.6 m. Calculate how hard the water

**A bar measuring 0.5 * 0.4 * 0.1 m is in a jar of water at a depth of 0.6 m. Calculate how hard the water presses on the bottom edge of the bar?**

We write down a short record of the condition of the problem.

Given:

a = 0.5 m;

b = 0.4 m;

c = 0.1 m.

h = 0.6 m.

We write the constants that we need for the calculation:

g = 10 H / kg;

p = 1000 kg / m ^ 3.

Let’s calculate:

F1 -? (force acting on the upper edge of the bar)

F2 -? (force acting on the lower edge of the bar).

p -?

Solution:

Let’s apply the formulas:

F1 = p1 * S; where p1 = pgh1.

Similarly:

F2 = p2 * S; p2 = pgh2.

S = a * b.

P = m (b) * g; m (s) = p (s) * V (m); m (in) = p (in) * a * b * c.

Substitute values and perform calculations:

p1 = 1,000 kg / m ^ 3 * 10 H / kg * 0.6 m = 6000 Pa;

p2 = 1000 kg / m ^ 3 * 10 H / kg * 0.7 m = 7000 Pa;

S = 0.5 m * 0.4 m = 0.2 m ^ 2;

V = 0.5 m * 0.4 m * 0.1 m = 0.02 m ^ 3;

F1 = 6000 Pa * 0.2 m ^ 2 = 1200 H;

F2 = 7000 Pa * 0.2 m ^ 2 = 1400 H;

m (c) = 1000 kg / m ^ 3 * 0.02 m ^ 3 = 20 kg;

p = 20 kg * 10 H / kg = 200 H.