A bar weighing 2 kg is located on an inclined plane with an angle of inclination of 30.

A bar weighing 2 kg is located on an inclined plane with an angle of inclination of 30. What force, directed parallel to the plane, must be applied to keep the bar at rest.

To find the value of the force applied to the specified bar, we project the acting forces onto the surface of the inclined plane: m * a = 0 (the bar must be at rest) = F – Fт * sinα = F – m * g * sinα, whence we express: F = m * g * sinα.

Constants and variables: m is the mass of the bar (m = 2 kg); g – acceleration due to gravity (g ≈ 10 m / s2); α is the inclination of the plane (α = 30º).

Let’s calculate: F = m * g * sinα = 2 * 10 * 1/2 = 10 N.

Answer: To hold the specified bar, a force of 10 N. is required.