# A bar weighing 2 kg is located on an inclined plane with an angle of inclination of 30.

August 28, 2021 | education

| **A bar weighing 2 kg is located on an inclined plane with an angle of inclination of 30. What force, directed parallel to the plane, must be applied to keep the bar at rest.**

To find the value of the force applied to the specified bar, we project the acting forces onto the surface of the inclined plane: m * a = 0 (the bar must be at rest) = F – Fт * sinα = F – m * g * sinα, whence we express: F = m * g * sinα.

Constants and variables: m is the mass of the bar (m = 2 kg); g – acceleration due to gravity (g ≈ 10 m / s2); α is the inclination of the plane (α = 30º).

Let’s calculate: F = m * g * sinα = 2 * 10 * 1/2 = 10 N.

Answer: To hold the specified bar, a force of 10 N. is required.

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