Let a block having the shape of a rectangular parallelepiped weighing m = 5 kg has dimensions: 10x20x25 cm.It is known from the problem statement that the block lies on the table with its larger facet, then the large facet of the bar will have an area:
S = 20 cm ∙ 25 cm = 500 cm ^ 2;
S = 0.05 m ^ 2.
From the side of the bar, a force F acts on the table, equal to its weight:
F = m ∙ g, where coefficient g = 9.8 H / kg.
To determine what pressure he creates on the table, we find the ratio:
p = F: S or p = m ∙ g: S.
Substitute the values of physical quantities in the calculation formula:
p = 5 kg ∙ 9.8 H / kg: (0.05 m ^ 2);
p = 980 Pa.
Answer: the bar creates a pressure of 980 Pa on the table.
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