A block weighing 2 kg lies on the table. The surface of the bar in contact

A block weighing 2 kg lies on the table. The surface of the bar in contact with the table measures 20 x 25 cm. What is the approximate pressure of the bar on the table?

m = 2 kg.

g = 10 N / kg.

a = 20 cm = 0.2 m.

b = 25 cm = 0.25 m.

P -?

The pressure of the force P is the ratio of the force F to the area S on which this force acts: P = F / S.

The bar presses on the table with its weight R. The weight of the body F is found by the formula: F = m * g, where m is the mass of the body, g is the acceleration of gravity.

The contact area of the bar with the table is rectangular, so S = a * b.

The bar pressure will be determined by the formula: P = m * g / a * b.

P = 2 kg * 10 N / kg / 0.2 m * 0.25 m = 400 Pa.

Answer: the pressure of the bar on the table is P = 400 Pa.