A body thrown from a horizontal tower 6m high fell 8m from the base of the tower. What is the movement of the body.
| July 28, 2021 | education
To find the displacement of the thrown body, we use the Pythagorean theorem (the vectors of horizontal and vertical displacements are perpendicular to each other): S = √ (Sv ^ 2 + Sg ^ 2).
Values of variables: Sв – vertical movement (tower height; Sв = 6 m); Sg – horizontal displacement (distance between the base of the tower under consideration and the place of fall; Sg = 8 m).
Let’s perform the calculation: S = √ (Sv ^ 2 + Sg ^ 2) = √ (6 ^ 2 + 8 ^ 2) = 10 m.
Answer: The body has moved 10 meters.
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