# A body was thrown in a horizontal direction from a tower 50 m high. Determine the initial speed

**A body was thrown in a horizontal direction from a tower 50 m high. Determine the initial speed of the body if it fell to the ground at a distance of 80 m from the base of the tower. Round up your answer to the nearest whole number. Acceleration of gravity is considered equal to 9.8 m / s2. Disregard air resistance.**

Data: h (tower height) = 50 m; L (distance from the base of the tower to the point where the stone falls) = 80 m.

Constants: by condition g (gravitational acceleration) = 9.8 m / s2.

To determine the initial horizontal speed of the stone, we will use the formula: Vg = L / t = L / √ (2h / g).

Let’s make a calculation: Vg = 80 / √ (2 * 50/10) = 25.04 m / s ≈ 25 m / s.

Answer: The stone in question was thrown from the tower at a speed of 25 m / s.