# A body weighing 1 kg was placed on an inclined plane. the coefficient of friction against the surface is 0.7.

A body weighing 1 kg was placed on an inclined plane. the coefficient of friction against the surface is 0.7. Find the friction force acting on the body if the angle of inclination of the plane to the horizon is 45 degrees

To find the friction force acting on a given body on an inclined plane, we use the formula: Ffr = μ * N = μ * m * g * cosα.

Constants and variables: μ – coefficient of friction on an inclined plane (μ = 0.7); m – body weight (m = 1 kg); g – acceleration due to gravity (g ≈ 10 m / s2); α is the angle of inclination of the plane (α = 45º).

Calculation: Ftr = μ * m * g * cosα = 0.7 * 1 * 10 * cos 45º = 4.95 N.

Answer: A friction force of 4.95 N acts on a given body on an inclined plane.

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