A body weighing 4 kg moves evenly along a horizontal plane. In this case, the thrust force is equal to 10 N. What is the coefficient of friction?
m = 4 kg.
g = 10 m / s ^ 2.
F = 10 N.
According to 1 Newton’s law, a body moves uniformly in a straight line if the action of forces on it is compensated.
4 forces act on the body.
The force F, with which the body is pulled, is compensated by the friction force Ffr: F = Ftr.
The force of gravity m * g is compensated by the reaction force of the support N: m * g = N.
The friction force Ffr is determined by the formula: Ffr = μ * N, where μ is the coefficient of friction.
Ftr = μ * m * g.
μ = Ftr / m * g = F / m * g.
μ = 10 N / 4 kg * 10 m / s ^ 2 = 0.25.
Answer: the coefficient of friction between the body and the surface is μ = 0.2.
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