A bullet weighing 10 g, flying horizontally at a speed of 300 m / s, hits a wooden block weighing 6 kg

A bullet weighing 10 g, flying horizontally at a speed of 300 m / s, hits a wooden block weighing 6 kg suspended on threads and gets stuck in it. Determine the height to which the block will rise.

Given: mp (bullet mass) = 10 g = 0.01 kg; Vp (horizontal speed of a bullet) = 300 m / s; mb (bar weight) = 6 kg.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Determine the speed of the bar after the bullet hit: V = mp * Vp / (mp + mb) = 0.01 * 300 / (0.01 + 6) = 0.5 m / s.

2) Calculate the height of the bar rise: (mp + mb) * V ^ 2/2 = (mp + mb) * g * h, whence h = V ^ 2 / (2 * g) = 0.5 ^ 2 / (2 * 10) = 0.0125 m (12.5 mm).

Answer: The bar will rise to a height of 12.5 mm.