A bullet with a speed of 400 m / s strikes the earthen rampart and penetrates it. What is the speed of the bullet when it has covered 99% of its path?
Data: V0 (bullet velocity before hitting the shaft) = 400 m / s; S1 (bullet path in question) = 0.99S (full path).
To calculate the speed of the bullet after passing 99% of the full path, we use the equality: (V0 ^ 2 – V2) / 2S1 = a = V0 ^ 2 / 2S, whence V0 ^ 2 – V2 = V0 ^ 2 * S1 / S; V2 = V0 ^ 2 – V0 ^ 2 * 0.99 and V = √ (V0 ^ 2 * (1 – 0.99)).
Let’s calculate: V = √ (400 ^ 2 * (1 – 0.99)) = 40 m / s.
Answer: After passing 99% of its path, the target bullet will have a velocity of 40 m / s.
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