A capacitor with a capacity of 20 μF is charged to a potential difference equal to 100 V. Find the energy of the capacitor.

These tasks: C (the capacity of the capacitor taken) = 20 μF (20 * 10 ^ -6 F); Δφ (potential difference to which the capacitor was charged) = 100 V.

The energy of the capacitor taken is determined by the formula: Wp = C * Δφ ^ 2/2.

Calculation: Wp = 20 * 10 ^ -6 * 100 ^ 2/2 = 0.1 J.

Answer: The capacitor taken has an energy of 0.1 J.

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