Initial data: Vн (vehicle speed before stopping in front of a traffic light) = 60 km / h (16.7 m / s); t (deceleration duration) = 2 s; before the traffic light, the car stopped (Vk = 0 m / s).
1) Vehicle acceleration (slow motion): Vk = 0 = Vn – a * t, whence a = Vn / t = 16.7 / 2 = 8.35 m / s2.
2) Braking distance: S = Vn ^ 2 / 2a = 16.7 ^ 2 / (2 * 8.35) = 16.7 m.
Answer: The braking distance is 16.7 m.
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