# A car traveling at a speed of 36 km / h begins to move with an acceleration of 0.2 m / s2.

A car traveling at a speed of 36 km / h begins to move with an acceleration of 0.2 m / s2. What path will the car cover in tenth second from the start of movement?

Distance traveled by car:
S = V0 * t + a * t² / 2, where V0 is the initial speed of the vehicle (V0 = 36 km / h = 36 * 1000/3600 = 10 m / s), and is the acceleration of the vehicle (a = 0.2 m / s²), t – time of movement of the car (s).
Distance covered by the car in tenth second:
S = S (10) – S (9) = 10 * 10 + 0.2 * 10² / 2 – 10 * 9 – 0.2 * 9² / 2 = 100 + 10 – 90 – 8.1 = 11.9 m …
Answer: The car will cover a distance of 11.9 m in the tenth second from the start of movement.

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