# A chord AB with a length of 16 cm is drawn in a circle with a radius of 10 cm. The tangents to the circle drawn through

**A chord AB with a length of 16 cm is drawn in a circle with a radius of 10 cm. The tangents to the circle drawn through points A and B intersect at point C. Find the length of the line segment AC.**

The height OH of the isosceles triangle AOB is so its median, then AH = BH = AB / 2 = 16/2 = 8 cm.

In the right-angled triangle AOH, we define the sine of the angle AOH. SinAOH = AH / AO = 8/10 = 0.8.

Since the radius of AO, by the property of the tangent, is perpendicular to the tangent AC, then the triangle AOC is rectangular, with AO = 10 cm, SinAOC = 0.8.

Then CosAOC = √ (1 – 0.64) = √0.36 = 0.6.

OC = AO / CosAOC = 10 / 0.6 = 50/3.

In a rectangular triangle AOC, AC ^ 2 = OC ^ 2 – AO ^ 2 = 2500/9 – 100 = (2500 – 900) / 9 = 1600/9.

AC = 40/3 = 13 (1/3) cm.

Answer: The length of the AC segment is 13 (1/3) cm.