A circle is inscribed in the ABCD quadrangle, AB = 10, CD = 16. Find the perimeter of the quadrangle.

If it was possible to inscribe a circle into the quadrangle ABCD, then the following condition must be met:

AB + CD = BC + AD (the sums of the opposite sides must be equal).

AB + CD = 10 + 16 = 26;

BC + AD = 26.

Find the perimeter of the quadrangle:

(AB + CD) + (BC + AD) = 26 + 26 = 52.

Answer: 52.



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