A crane with an area of 30 cm2 was installed in a tank filled with oil at a depth of 4 m.

A crane with an area of 30 cm2 was installed in a tank filled with oil at a depth of 4 m. With what force does the oil press on the tap?

To find out the force of oil pressure in the tank on the indicated crane, we use the equality: ρн * g * h = Phydr (pressure of the oil column) = Fх / S, from where we express: Fх = ρн * g * h * S.

Const: ρн – oil density (ρн = 650 … 1050 kg / m3; we take ρн = 850 kg / m3); g – acceleration due to gravity (g ≈ 9.81 m / s2).

Data: h – considered depth (h = 4 m); S is the area of the indicated crane (S = 30 cm2; in the SI system S = 30 * 10-4 m2 = 3 * 10-3 m2).

Let’s perform the calculation: Fх = ρн * g * h * S = 850 * 9.81 * 4 * 3 * 10-3 ≈ 100 N.

Answer: The force of oil pressure on the indicated valve is 100 N.