# A cylinder with a capacity of 40 liters contains oxygen weighing 2.6 kg. At what temperature there is a danger

**A cylinder with a capacity of 40 liters contains oxygen weighing 2.6 kg. At what temperature there is a danger of explosion if the permissible value of the explosion is 50 × 10 ^ -3pascal.**

V = 40 l = 0.04 m3.

m = 2.6 kg.

M (O2) = 0.032 kg / mol.

R = 8.31 m2 * kg / s2 * ° K * mol.

P = 50 * 10 ^ 3 Pa.

T -?

Let us write the Mendeleev-Cliperon equation for oxygen in the cylinder: P * V = m * R * T / M, where P is the maximum pressure that the cylinder can withstand, V is the volume of the cylinder, m is the mass of oxygen, R is the universal gas constant , T is the absolute temperature, M is the molar mass of the gas.

Since the oxygen molecule consists of two atoms, then according to the periodic table, the molar mass is M (O2) = 0.032 kg / mol.

T = M * P * V / m * R.

T = 0.032 kg / mol * 50 * 103 Pa * 0.04 m3 / 2.6 kg * 8.31 m2 * kg / s2 * ° K * mol = 3 ° K.

Answer: the oxygen temperature should not exceed T = 3 ° K.