A cylindrical body floats in a liquid as shown in the figure (the volume of the above-water part refers to the volume

A cylindrical body floats in a liquid as shown in the figure (the volume of the above-water part refers to the volume of the underwater one as 1: 3). Determine the density of the liquid if the density of the floating body is 600 kg / m3.

The mass of the body can be calculated by the formula: m = ρ0 * v where ρ0 is the density of the body, v is the volume.
There are two forces acting on the body. Gravity equal to:
F = mg = ρ0vg
and the strength of Archimedes:
Fa = ρgv / 3 where ρ is the density of the liquid.
From the condition of bodies floating, these forces are equal.
ρ0vg = ρgv / 3
ρ0 = ρ / 3
ρ = ρ0 * 3 = 600 * 3 = 1800 kg / m ^ 2.



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