A dog weighing 32 kg jumps on a stationary cart weighing 10 kg; speed of the dog during a jump of 25 m / s, determine the speed of the cart with the dog
Initial data: mt (mass of a stationary bogie) = 10 kg; mc (dog weight) = 32 kg; Vs (speed of the dog during the jump) = 25 m / s.
The speed of the joint movement of the cart with the dog can be determined using the law of conservation of momentum: mc * Vc = (mc + mt) * V, whence V = mc * Vc / (mc + mt).
Calculation: V = 32 * 25 / (32 + 10) = 800/42 ≈ 19 m / s.
Answer: The speed of the dog cart is 19 m / s.
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