A force of 300N acts on the left arm of the lever, and a load weighing 10 kg is suspended to the right arm. The left arm of the lever is 10 cm. What is the right arm of the lever, if it is in equilibrium?
Fl = 300 N.
Ll = 10 cm = 0.1 m.
g = 10 N / kg.
mp = 10 kg.
When the lever is in equilibrium, the moments of forces that act from its opposite sides are equal to each other: Ml = Mp.
The moment of force M is called the product of the applied force F to the smallest distance from the application of force in the axis of rotation of the lever L: M = F * L.
Fl * Ll = Fp * Lp.
On the right side, the weights act on the lever by the force of their weight, the value of which is determined by the formulas: Fп = mп * g.
Fl * Ll = mp * g * Lp.
Lp = Fl * Ll / mp * g.
Lp = 300 N * 0.1 m / 10 kg * 10 N / kg = 0.3 m.
Answer: the right arm of the lever is Lp = 0.3 m.
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