# A gas with a volume of 6m3 is under a pressure of 1.9 * 100000 Pa. What is the work done with its isobaric

A gas with a volume of 6m3 is under a pressure of 1.9 * 100000 Pa. What is the work done with its isobaric heating from 285 to 360 K

V1 = 6 m3.

P = 1.9 * 100,000 Pa.

T1 = 285 ° C.

T2 = 360 ° C.

A -?

Isobaric is a process in which the gas pressure, throughout the entire process, remains unchanged P = const.

The work of gas A in the isobaric process is determined by the formula: A = P * (V2 – V1).

For the isobaric process, the Gay-Lussac law is valid: V1 / T1 = V2 / T2.

V2 = V1 * T2 / T1.

V2 = 6 m3 * 360 ° K / 285 ° K = 7.58 m3.

A = 1.9 * 100,000 Pa * (7.58 m3 – 6 m3) = 300,000 J.

Answer: with isobaric heating, the gas did work A = 300,000 J.

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