# A car with a mass of 20 tons, moving at a speed of 0.56 m / s, collides with a platform

December 31, 2020 | education

| **A car with a mass of 20 tons, moving at a speed of 0.56 m / s, collides with a platform with a mass of 8 tons, determine their speed after coupling.**

I use the law of conservation of momentum:

m1 * v1 + m2 * v2 = m1 * v3 + m2 * v4

Given:

m1 = 20 t.

m2 = 8 t.

v1 = 0.56 m / s

v2 = 0 m / s

V = v3 = v4 – the total speed of the car and platform after coupling

20 * 10 ^ 3 * 0.56 = 20 * 10 ^ 3 * V + 8 * 10 ^ 3 * V

20 * 0.56 = V * (20 + 8)

V = 11.2 / 28

V = 0.4 m / s – speed after coupling the car and platform

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