A helicopter with a mass of 27 tons lifts a load of 15 tons with an acceleration of 0.6 m / s2.

A helicopter with a mass of 27 tons lifts a load of 15 tons with an acceleration of 0.6 m / s2. Find the thrust force of the helicopter and the force acting from the side of the cargo on the aircraft’s trailer mechanism

mw = 27 t = 27000 kg.

mg = 15 t = 15000 kg.

a = 0.6 m / s2.

g = 9.8 m / s2.

Fт -?

P -?

Let us write Newton’s 2 law for a helicopter in vector form: mw * a = Ft + mw * g + P, where mw is the mass of the helicopter, a is the acceleration of the helicopter, Ft is the thrust force of the helicopter, mw * g is the force of gravity that acts on the helicopter , P is the weight of the cargo.

ОХ: mw * a = Ft – mw * g – P.

Ft = mw * a + mw * g + P.

We express the weight of the cargo P by the formula: P = mg * g.

P = 15000 kg * 9.8 m / s2 = 147000 N.

Ft = 27000 kg * 0.6 m / s2 + 27000 kg * 9.8 m / s2 + 147000 N = 427800 N.

Answer: P = 147000 N, Ft = 427800 N.