A lead ball weighing 2.2 kg moves on a horizontal surface at a speed of 6 m / s. Determine its kinetic energy.

m = 2.2 kg.

V = 6 m / s.

Ek -?

The kinetic energy of motion of the body Ek is determined by the formula: Ek = m * V ^ 2/2, where m is the mass of the lead ball, V is the speed of the ball.

Ek = 2.2 kg * (6 m / s) ^ 2/2 = 39.6 J.

Answer: the kinetic energy of the lead ball is Ek = 39.6 J.

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