A liquid weighing 1.36 kg takes up a volume of 100 cm3. What kind of liquid is it?

Initial data: m (mass of an unknown liquid) = 1.36 kg, V (volume that an unknown liquid occupies) = 100 cm ^ 3.

SI system: V = 100 cm ^ 3 = 100 * 10 ^ -6 m ^ 3.

Let’s calculate the density and use the tables to determine which liquid can have the given parameters.

ρ = m / V = 1.36 / (100 * 10 ^ -6) = 13 600 kg / m ^ 3 (corresponds to the tabular value of the density of mercury).

Answer: The unknown liquid is mercury.



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