A load weighing 0.2 kg is suspended on a spiral spring with a stiffness of 20 N / m.
| September 28, 2021 | education
A load weighing 0.2 kg is suspended on a spiral spring with a stiffness of 20 N / m. Determine the period of free oscillations of the load.
Given: m (mass of the load performing free vibrations) = 0.2 kg; k (coefficient of stiffness of the taken spiral spring) = 20 N / m.
The period of free oscillations of the load on the taken spiral spring is calculated by the formula: T = 2 * Π * √ (m / k).
Let’s perform the calculation: T = 2 * 3.14 * √ (0.2 / 20) = 0.628 s.
Answer: The weight on the coil spring oscillates with a period of 0.628 s.
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