# A load weighing 1.5 kg was suspended from a spring with a stiffness of 500 N / m.

A load weighing 1.5 kg was suspended from a spring with a stiffness of 500 N / m. With what frequency will such a pendulum oscillate?

A spring pendulum is a spring with a rigidity k of which a weight of mass m is attached.

Let us find the oscillation period T of the spring pendulum:

T = 2 * п * √ (m / k),

where п = 3.14 is the number of Pi;

m = 1.5 kg is the weight of the cargo;

k = 500 N / m – the stiffness of the pendulum spring.

Means

T = 2 * 3.14 * √ (1.5 / 500) = 0.314 s.

The oscillation frequency V of a spring pendulum is inversely proportional to its oscillation period, hence:

V = 1 / T = 1 / 0.314 = 3.2 Hz.

Answer: The oscillation frequency of the spring pendulum is 3.2 Hz.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.