A paraffin ball with a volume of 520 cm ^ 3 was dipped into water. determine the force of Archimedes acting on the ball.

univerkov | June 30, 2021 | education

Initial data: V (volume of the paraffin ball) = 520 cm3.

Reference data: g (acceleration due to gravity) = 9.81 m / s2 ≈ 10 m / s2; ρw (water density) = 1000 kg / m3; by condition ρp (paraffin density) = 900 kg / m3.

SI system: V = 520 cm3 = 520 * 10-6 m3.

1) The volume of a part of the ball immersed in water: V1 / V = ρp / ρw and V1 = ρp * V / ρw = 900 * 520 * 10-6 / 1000 = 468 * 10-6 m3.

2) The force of Archimedes, which acts on a paraffin ball in water: Fа = ρw * g * V1 = 1000 * 10 * 468 * 10-6 = 4.68 N.

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