a-Particle (the nucleus of a helium atom), the kinetic energy of which is 8 * 10 ^ -17 J, flies into a uniform magnetic
a-Particle (the nucleus of a helium atom), the kinetic energy of which is 8 * 10 ^ -17 J, flies into a uniform magnetic field with an induction of 0.1 T perpendicular to its lines of force. Determine the force acting on the particle, the radius of the circle along which it moves, and the period of its revolution.
In order to find a formula for a solution, you need to look at what is given to us:
B = 0.1 T;
sin A = 1;
q = 3.2 * 10 ^ -19 C;
m = 6.64 * 10-27 Kg;
Ek = 8 * 10 ^ -17 J;
Let’s write down the formulas that we will use:
E = m * u ^ 2/2;
u ^ 2 = 2 * E / m;
It should be noted that u is a constant: u = 1.5523 * 10 ^ 5 m / s.
Find F by the formula:
F = q * u * B * sin A = q * √ (2 * E / m) * B * sinA;
Let’s substitute:
F = 3.2 * 10 ^ -19 * √ (2 * 8 * 10 ^ -17 / 6.64 * 10 – 27) * 0.1 * 1;
F = 4.967 * 10 ^ -15 H;
Let’s find R, according to the formula:
R = m * u / (q * B);
Let’s substitute:
R = 6.64 * 10 ^ -27 * √ (2 * 8 * 10 ^ -17 / 6.64 * 10 – 27) / (3.2 * 10 ^ -19 * 0.1);
R = 0.0322 m;
R = 3.22 cm.
Find T, by the formula:
T = 2pi * R / u;
T = 2pi * 0.0322 / (1.5523 * 10 ^ 5);
T = 1.3 * 10 ^ -6 s.
Answer: T = 1.3 * 10 ^ -6 s.