A person lifts a stone weighing 600 N using the AC lever. With what force does a person

A person lifts a stone weighing 600 N using the AC lever. With what force does a person act on the lever if AB = 1.2 m and BC = 0.5 m?

To determine the value of the force acting on the lever from the side of a person, we will use the equality: P * LBC = F * LAB, from where we express: F = P * LBC / LAB.

Values of variables: P – weight of the lifted stone (P = 600 N); LBC – small lever arm (LBC = 0.5 m); LAB – larger lever arm (LAB = 1.2 m).

Let’s calculate: F = P * LBC / LAB = 600 * 0.5 / 1.2 = 250 N.

Answer: A force of 250 N. must act on the lever from the side of a person.



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