A person running at a speed of 10 m / s catches up with a cart moving at a speed of 1 m / s and jumps on it.

A person running at a speed of 10 m / s catches up with a cart moving at a speed of 1 m / s and jumps on it. how fast will the cart move after that? the mass of a person and a carriage, respectively, 60 and 40 kg.

Initial data: V1 (speed with which the person ran) = 10 m / s; V2 (own trolley speed) = 1 m / s; m1 (human weight) = 60 kg; m2 (trolley weight) = 40 kg.

The speed at which the cart will move is determined using the law of conservation of momentum: m1 * V1 + m2 * V2 = (m1 + m2) * V1,2, whence V1,2 = (m1 * V1 + m2 * V2) / (m1 + m2).

Let’s calculate: V1.2 = (60 * 10 + 40 * 1) / (60 + 40) = 640/100 = 6.4 m / s.

Answer: The cart will move at a speed of 6.4 m / s.

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