A piece of iron with a volume of 0.2m3 is completely submerged in water.

A piece of iron with a volume of 0.2m3 is completely submerged in water. Determine the buoyancy force acting on this piece?

These tasks: V (the volume of a piece of iron completely immersed in water) = 0.2 m3.

Reference values: g (acceleration due to gravity) ≈ 10 m / s2; according to the condition ρw (water density) = 1000 kg / m3.

The required buoyancy force acting on the considered piece of iron in water is calculated by the formula: Fa = ρw * g * V.

Let’s perform the calculation: Fa = 1000 * 10 * 0.2 = 2 * 103 N (2 kN).

Answer: A buoyant force of 2 kN will act on the piece of iron in question.



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