A point of movement along a circle with a radius of R = 4m according to the law S = 8-2. The moment in time when the normal acceleration of a point is 9 m / will be
Data: R (radius of a circle) = 4 m; the law of motion S = 8 – 2t ^ 2; an (required normal acceleration) = 9 m / s2.
Normal acceleration: an = V2 / R = (S ‘) 2 / R = ((8 – 2t2)’) ^ 2 / R = (-4t) ^ 2 / R = 16t ^ 2 / R, whence we express: t = √ (an * R / 16) = √ (9 * 4/16) = 1.5 s.
Answer: the moment in time is 1.5 s.
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