# A projectile weighing 2 kg, flying at a speed of 300 m / s, hits a target with sand weighing 100 kg

March 28, 2021 | education

| **A projectile weighing 2 kg, flying at a speed of 300 m / s, hits a target with sand weighing 100 kg and gets stuck in it. With what speed and in what direction the target will move after the projectile hit (the target is motionless).**

Initial data: m1 (projectile mass) = 2 kg; V1 (projectile speed) = 300 m / s; m2 (mass of a stationary target with sand, V2 = 0 m / s) = 100 kg.

The speed of the target after the projectile hit is determined using the law of conservation of momentum: m1 * V1 = V1.2 * (m1 + m2) and V1.2 = m1 * V1 / (m1 + m2).

Calculation: V1.2 = 2 * 300 / (2 + 100) = 600/102 ≈ 5.88 m / s.

Answer: The target will move at a speed of 5.88 m / s in the direction of the velocity vector of the projectile.

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