A projectile weighing 20 kg, flying horizontally at a speed of 500 m / s, hits a platform with sand weighing 10 tons and gets stuck in the sand. How fast did the platform begin to move?
To find out the speed acquired by the specified platform, we use the equality: mc * Vc + mpl * Vpl = (mc + mpl) * V, from where we can express: V = (mc * Vc + mp * Vpl) / (mc + mpl).
Data: mс – mass of the projectile (mс = 20 kg); Vс – initial velocity of the projectile (Vс = 500 m / s); mpl is the mass of the platform (mpl = 10 t = 10 ^ 4 kg); Vп – initial platform speed (Vп = 0 m / s).
Let’s calculate: V = (mc * Vc + mpl * Vpl) / (mc + mpl) = (20 * 500 + 10 ^ 4 * 0) / (20 + 10 ^ 4) = 0.998 m / s.
Answer: The specified platform should start moving at a speed of 0.998 m / s.
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